How do you make a 0.1 M EDTA solution?

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How do you make a 0.1 M EDTA solution?

Preparation and Standardization of 0.1 M Disodium Edetate (EDTA)

  1. Take about 100 ml of water in a cleaned and dried 1000 ml volumetric flask.
  2. Add about 37.2 gm of Disodium Edetate with continues stirring.
  3. Add more about 700 ml of water mix.
  4. Make up the volume 1000 ml with water.

How do you make 0.02 M EDTA?

0.02 M EDTA

  1. 7.44 g disodium EDTA.
  2. 1 liter water.
  3. NaOH.

What is equivalent weight of EDTA?

186.12

EDTA (Disodium)
Chemical Formula [(HO2CCH2-)(NaO2CCH2-)N-CH2]2·2H2O
Formula Weight 372.24
Equivalent Weight 186.12 (Molar = 2 Normal)*
CAS No. 6381-92-6

How do you calculate EDTA molarity?

  1. Molarity.
  2. EDTA (mol / L)
  3. = 0.01000 L × 0.01603 mol / L ×
  4. 1 mol EDTA.
  5. 1 mol Zinc.
  6. ×
  7. 0.01625 L.

How do you make na2 EDTA?

To prepare EDTA at 0.5 M (pH 8.0): Add 186.1 g of disodium EDTA•2H2O to 800 mL of H2O. Stir vigorously on a magnetic stirrer. Adjust the pH to 8.0 with NaOH (~20 g of NaOH pellets).

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What is the molarity of EDTA?

Molarity of EDTA = 0.01135 M The hardness of water is calculated in terms of the weight of CaCO3 (1 ppm = 1 mg/L).

How can I prepare EDTA solution from EDTA?

Take aliquots of it to dilute it to 1/2, 1/5, 1/20 and 1/100 of the original strength with distilled water. Then you have your required solutions. there are two ways you can prepare EDTA solution of different concentration.

What is the mole ratio of EDTA in this reaction?

The same is true for EDTA. EDTA is a tetradentate ligand which can bind to up to four different metal ions. However, in its normal role, it is used to determine water hardness according to the following equation, Since the mole ratio in the reaction is 1:1, then 0.1 M EDTA is also 0.1 N EDTA.

How many protons are required to prepare EDTA without buffering effect?

However, since this question is asking for a preparation of EDTA without a buffering effect, I will assume all four protons will be used. (0.1N EDTA) x (1M equivalent Na2EDTA.2H2O/ 4 N equivalent protons ) x (1L/1000ml) x (250ml solutionl) x (372.24 grams/ mole) = 2.33 grams Na2EDTA.2H2O required.

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How do you convert EDTA to mg/L for water hardness?

0.01 molar calcium carbonate (which has a molecular weight of 100) is 1 gm/L or 1000 mg per litre, thus each millilitre of edta solution is equivalent to one milligram of calcium carbonate, simply multiply the volume of the sample by the titration value and you have the result in mg/L (ppm) for water hardness.

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