## How do you find the last non zero digits?

= 14 * 13 * 12 * 11 * 2 * 9 * 8 * 7 * 6 * 3 * 2 * 1 Now we can get last non-zero digit by multiplying last digits of above factors! In n! a number of 2’s are always more than a number of 5’s. To remove trailing 0’s, we remove 5’s and equal number of 2’s. Let a = floor(n/5), b = n \% 5.

**What is the last nonzero digit of 96?**

How to find the last non zero digit in 96 factorial. 96 = 5*19+1. i.e a=19 and b=1.

**What are the non zero numbers?**

Non-zero whole numbers are whole numbers that explicitly exclude zero. Non-zero whole numbers are 1, 2, 3, 4, 5, 6 ⋯ .

### What is a non zero integer?

The nonzero integers are [rational] integers other than zero, and thus have positive absolute value; they may be positive or negative numbers.

**What is the last nonzero digit in 20?**

So the last non-zero digit is 4. There are two methods you may use to find the last non-zero digit in 20! The last non-zero digit in N! is same as the last non-zero digit in (N/5)! ×(2^(N/5))×(N/5rem)!

**What is the last nonzero digit of 100?**

Hence, 4 is the last non-zero digit of 100!

## How to find the last non-zero digit in 120?

Given a number n, find the last non-zero digit in n!. Input : n = 5 Output : 2 5! = 5 * 4 * 3 * 2 * 1 = 120 Last non-zero digit in 120 is 2. Input : n = 33 Output : 4 Recommended: Please solve it on “ PRACTICE ” first, before moving on to the solution.

**How to find the last non zero digit of a factorial?**

Their composite product’s last non-zero digit will be the last non zero digit of n factorial. In general, last non zero digit of n factorial is given by last non zero of 2^a * a! * b! Where n = 5a + b Example : Find the last non-zero digit of 33!

**What is the last two digits after pulling out 2 from above?**

Now If a is odd, 7 a 2 + a is even so which contributes another 2. So 1750 a 2 +250a has two zeroes. If a is even, 1750 a 2 +250a clearly gives two zeroes. So the last two digits after pulling out 2 from the above is 12.

### How many zeroes does 1750 a 2 +250A + 12 have?

So last two digits of this expression depends on 1750 a 2 +250a + 12 We try to find the last two digits of 1750 a 2 +250a. Taking 250 common Now If a is odd, 7 a 2 + a is even so which contributes another 2. So 1750 a 2 +250a has two zeroes. If a is even, 1750 a 2 +250a clearly gives two zeroes.