## How many four digit positive integers have exactly two even and two odd pairwise different digits?

Therefore, there are 4536 four-digit numbers with distinct digits.

**How many 4 digit numbers have all their digits even or odd?**

So even number can be chosen in 4*5*5*5=500 ways. So total 625+500=1125 4-digit numbers have all their digits either even or odd.

### How many 4 digit numbers with distinct digits can be formed with the digits 1 0 8 and 2?

Hence 4536 is the number of possible arrangements of four distinct digit numbers.

**How many 4 digit number with distinct digits are there such that the sum of digits of each of these number is an odd natural number?**

we have 10 digits 0 to 9. To get 4 digit number with distinct digit, we need to choose 4 digit from 10. To choose 4 digit from 10 digit we can select them by \comb{10, 4} ways. Since the question asked for 4 digit number with odd sum of all 4 digits, we can not choose them as simple.

#### How many 4 digit numbers can be formed with exactly 3 distinct digits in them?

There are 9×9×8×7 4-digit numbers that have 4 different digits. There are 9×9×8 4-digit number that have 3 different digits.

**How many even 4 digit whole numbers are there * 2 points?**

Since there are 5 single digit even numbers that are 0, 2, 4, 6, 8. Therefore the number of 4 digit even numbers are …. – At tens and hundreds position we can have either of the 10 numbers.

## What is the total number of 4 digit numbers with odd digits?

Now, the number of ways pqrs can contain either all even digits or odd digits is: 625+500 = 1125 ways. Hope this explanation helps. So, total number of 4 digit numbers with odd digits can be calculated as = 5 × 5 × 5 × 5 = 625 But in this case, the numbers can’t with zero.

**How many ways can an odd number be chosen?**

So odd number can be chosen in 5*5*5*5=625 ways. 1st position can have any of the 4 digits (2,4,6,8) excluding 0.Since if the 1st position will have 0 then the number will no longer be a 4 digit number. But the 2nd,3rd & 4th positions can have any of the 5 digits. So even number can be chosen in 4*5*5*5=500 ways.

### How many 4 digit numbers can start with 0?

Note that a four digit number does not start with 0. Since the number cannot start with 0, there are 9 choices for the leftmost of the four digits. After choosing the leftmost digit, we will need to either choose 2 odd numbers and 1 even number or choose 2 even numbers and 1 odd number.

**How many ways can P be filled with 5 even digits?**

The first digit cannot be 0 other wise, the number would not be a 4 digit number. So, p can only contain 4 digits (2,4,6,8). q, now, can be any of the 5 even digits (0,2,4,6,8) and thus be filled in 5 ways. Remember, p is non zero, so q can be zero.