What is the velocity of the ball when it returns to the ground?
Conclusion: The magnitude of the velocity of the ball is 26.3 m/s for the parabolic motion just before it hits the ground and this greater than the 17.1 m/s for the velocity of the ball that falls straight downward.
When a ball is thrown upward What are its velocity and acceleration at its highest point?
On the way up, its acceleration is downward and its velocity is upward, and at the highest point both its velocity and acceleration are zero.
What was the maximum height reached by the ball?
Answer: 81.6 m. The height reached is the average velocity times this time 4.08 s, with v(avg) = [v(initial) + v(final)] / 2 with v(final) = 0. v(avg) = v(initial) / 2 = 40 m/s / 2 = 20 m/s.
When the golf ball returns to the ground the vertical velocity will increase or decrease?
(c) The velocity in the vertical direction begins to decrease as the object rises; at its highest point, the vertical velocity is zero. As the object falls towards the Earth again, the vertical velocity increases again in magnitude but points in the opposite direction to the initial vertical velocity.
What is the acceleration when a ball is thrown upwards?
If you throw the ball upward with a speed of 9.8 m/s, the velocity has a magnitude of 9.8 m/s in the upward direction. Now the ball is under the influence of gravity, which, on the surface of the Earth, causes all free-falling objects to undergo a vertical acceleration of –9.8 m/s2.
When a ball is thrown upward its acceleration is?
When you throw a ball up in the air, its direction/velocity on the way up, although it rises up into the air, is actually downward. On its way up, its speed decreases, until it momentarily stops at the very top of the ball s motion. Its acceleration is -9.8 m/s^2 at the very top.
What happens when a ball is thrown vertically upward?
When the body is thrown upwards, it moves up until the velocity of the ball becomes zero and the force exerted on it becomes zero. After that the ball reaches the ground with the acceleration due to gravity with the zero velocity. When the ball goes up, the height of the ball increases and it also moves up.
When a ball is thrown vertically upward it continues upward until it reaches?
Critical Thinking When a ball is thrown vertically upward, it continues upward until it reaches a certain position, and then it falls downward. At that highest point, its velocity is instantaneously zero.
When a ball is thrown vertically upwards and reaches its maximum height it has?
So at the maximum height, the velocity of the body is zero. Also at the maximum height, the acceleration of the body will be constant. This acceleration will be the acceleration due to gravity i.e., a=g at hmax .
When a ball is thrown vertically upward it returns to the thrower?
A ball thrown vertically upward returns to the thrower after 6 s. The ball is 5 m below the highest point at t = 2 s. The time at which the body will be at same position, (take g = 10 m/s 2 ).
How do you calculate the velocity of a vertically thrown ball?
If a ball is thrown vertically upwards with an initial velocity V0then here is a set of formula for your quick reference. 1) Maximum height reached = H = V02/ (2 g) 2) Velocity at the highest point = 0 3) Time for upward movement = V0/g 4) Time for downward movement = V0/g 5) Total time of travel in air = (2 V0)/g
What is the final velocity of the ball when it stops?
After a certain time period t, the ball reaches a height beyond which it can’t move upwards anymore and stops there i.e. its velocity becomes zero at that height. And for this upward movement, the final velocity v2 is 0 because the ball has stopped at the end of this upward traversal.
What is the maximum height of the ball after 4 s?
The maximum height reached by the ball (c). After 3 second, it starts to fall down. Hence after 4 s, the ball is at a height of 40 m above the ground. Was this answer helpful?