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What is the area of the largest rectangle that can be inscribed in a semi circle of radius 10?

Posted on August 20, 2022 by Author

What is the area of the largest rectangle that can be inscribed in a semi circle of radius 10?

54 square inches
A rectangle is inscribed in a semicircle of radius 10 cm. What is the area of the largest rectangle we can inscribe? Amax = xw = (5 / 2)(10 / 2) = 100 Page 7 A poster is supposed to have margins of 1 inch on the left and right and 1.5 inches on top and on bottom. The printed area is supposed to be 54 square inches.

What is the area of the largest rectangle that can be inscribed in a semi circle of radius 2m?

The answer is 8 sq. units. It can be easily proven that the largest rectangle in a given circle is a square.

What is the area of the largest rectangle that can be inscribed in a semicircle of radius 5cm?

25 square units
The area of the largest rectangle that can be inscribed in a semi-circle of radius 5 is 25 square units.

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How do you inscribe a rectangle in a circle?

Since the diameter goes through the center, the intersection of any two diameters is a point on both diameters and must be the center. Guide students in constructing a rectangle inscribed in a circle by constructing a right triangle (as in the Opening Exercise) and rotating the triangle about the center of the circle.

What kind of rectangle with a maximum area can be inscribed in a circle?

square
So the rectangle of maximum area inscribed in a circle is a square.

How do you find the maximum area of a rectangle in a circle?

Since x must be positive, then x = r/√2. Thus, x = r/√2 and y = r/√2. Solving for the width and height and noting 2r is equal to the diameter d we have: The width and height have the same length; therefore, the rectangle with the largest area that can be inscribed in a circle is a square.

How do you find the area of a shaded semicircle?

The area of a semicircle can be calculated using the length of radius or diameter of the semicircle. The formula to calculate the area of the semicircle is given as, Area = πr2/2 = πd2/8, where ‘r’ is the radius, and ‘d’ is the diameter.

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