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How many 4 digit numbers can be formed using the digits 1 2 3 4 such that at least one digit is repeated?

Posted on August 31, 2022 by Author

How many 4 digit numbers can be formed using the digits 1 2 3 4 such that at least one digit is repeated?

936 4 digit numbers
Hence, there are 936 4 digit numbers formed from 1, 2, 3, 4, 5, 6 with at least one digit repeating.

How many 4 digit numbers can be formed with the digits 1 2 3 4 5 6 digit repeated any number of times in any arrangement?

Since there is no restriction on repetition of digits, each one of the hundred’s, ten’s and unit’s digits can be filled in 6 ways. Hence, the required number of numbers=(6×6×6)=216.

How many four digit odd numbers can be formed using the digits?

Complete step-by-step answer: And the hundred’s also the same, 8 possible numbers, and coming to the ten’s place, we will have only 7 possible numbers to place in it. So the number of four-digit odd numbers can be formed is 2240.

How many 4 digit NOS can be formed?

The smallest 4-digit number is 1,000 and the largest 4-digit number is 9,999, and there are a total of 9000 numbers from 1000 to 9999. We can make many four-digit numbers by using digits from 0 to 9 but we need to remember that the thousands place in a 4-digit number should not be 0.

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How many 4 digit numbers can be formed by using the digits 0 to 7 without repetition?

Answer is 840! This is a question of permutation and combination.

How many 4 digit odd numbers can be formed if no digit is repeated?

How many four-digit odd numbers do not use any digit more than once? The answer is C, 2240. Explanation from the book makes more sense now that I’ve thought about it a bit more.

How many 4 digit number can be formed with the digits 5 9 1 and 3 only?

How many four digit number can be formed with the digits 5,9,1 and 3 only? 64.

How many different 4 digit numbers can be formed from the digits 2 3 4 and 6 if each digit is used only once in a number?

Hence, Option (C) 24 is the correct answer.

How many 4-digit odd numbers are there?

There are five odd numbers: 1,3,5,7,9. For a 4-digit number to be odd, the last digit should be an odd number. Starting with the last ( ones) digit, the number of 4-digit numbers that can be formed without repeating any digit is:

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What is the required probability of 4 digits without repetition?

The number of ways that the four digits formed by the digits 1, 2, 3 4 without repetition = 4! Therefore, the required probability is = 12/ 4! Was this answer helpful?

What 3 numbers can be combined with 4 to make 42?

If 4 is the first digit the second digit can be 2, 6, or 8 (still have to save 7 for last. So 4 can be combined with any of these 3 numbers, let’s pick 2. Now our choices for digits 3 and 4 are 6 and 8, so all the choices beginning with 42 are just 42687 and 42867.

What is the total number of possible 4 digit numbers?

Number of 4 digit numbers (0–9) with at least one digit repeated= (Total number of possible 4 digit numbers) – (Total number of 4 digit numbers having no digit repeated) First digit can be among (1–9), 0 can’t be there at the first place .Thus,total possibilities=9

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