How does radius affect electric flux?
– The total electric flux through any closed surface is proportional to the total electric charge inside the surface. Point Charge Inside a Spherical Surface: – The flux is independent of the radius R of the sphere.
How will the flux through a spherical shell change if the radius of the shell is doubled?
Now, if we double the radius of the sphere, no change will be there as we can see that the electric flux does not depend on the radius of the sphere. Hence, there will be no change in the flux if the radius of the spherical shell is doubled.
Will the electric flux originating from a charged sphere change if the radius of the sphere is doubled?
If the radius is doubled the value of the electric flux will remain constant.
What will be the effect on electric flux if the area of the surface enclosing the charge is doubled?
If the area is doubled, the electric flux will also gets doubled. When area enclosed by the charge is doubled, A’ = 2A. New electric flux is given by : So, if the area is doubled, the electric flux will also gets doubled.
Why does flux not depend on radius?
If the radius of the spherical Gaussian surface is doubled, the surface area will increase by 4 times. On the other hand, the electric field at all points on the bigger surface will decrease by a factor of 4. Hence the flux through the surface remains the same.
Does flux depend on charge?
Electric flux is dependent on the charge enclosed by the surface. It also depends on the magnitude and direction of the electrical field. Note: The electric field lines flow from positive to negative charges.
How will this flux be affected if the radius of the surface is doubled?
If the radius of the Gaussian surface is doubled, the outward electric flux will remain the same.
How would the flux changes if the radius of the Gaussian surface is doubled and why?
Electric flux piercing out through a surface depends on the net charge enclosed inside a body. It does not depend on the size of the body. If the radius of the Gaussian surface is doubled, then the flux passing through the surface remains the same i.e., −103 N m2/C.
What happens to the net electric flux through the surface of a sphere when the charge inside the sphere is doubled?
If the radius of a spherical Gaussian surface is doubled when a point charge is inside, the total flux through the surface is doubled. If the point charge inside the Gaussian surface is tripled, the total flux through the surface must be tripled.
On which factors electric flux depends?
The numerical value of the electric flux depends on the magnitudes of the electric field and the area, as well as the relative orientation of the area with respect to the direction of the electric field.
How would the flux change if the radius of the Gaussian surface is halved?
If the radius of the Gaussion surface enclosing a charge q is halved, how does the electric flux through the Gaussion surface change? As ϕ=q∈0, so flux does not depend upon the radius of Gaussion surface, it will remain unchanged.
What is the relation between electric intensity and electric flux?
The electric field intensity of a point due to a number of a charge is equal to the vector sum of an electric field intensity of individual charge. The number of electric lines of force passing through an area held perpendicularly is called electric flux.
What happens to electric flux when radius is reduced?
Electric flux through a surface on a simpler note is nothing but no. of electric field lines passing normally through the surface. Now,if we gonna change the radius, say double it or reduce it by half, still you can see that the no. of electric field lines passing out out of the sphere is still the same and all of them pass normally as well.
What happens to the electric flux through a Gaussian surface?
A spherical gaussian surface surrounds a point charge $q$. Describe what happens to the: flux through the surface if 2) The radius of the sphere is doubled Our teacher said the electric flux will not change 3) The shape of the surface is changed to that of a cube
What happens to the electric field if the radius is halved?
The electric field at the surface of the sphere and the total flux through the sphere are determined. 1).What happens to the flux and the magnitude of The electric field if the radius of the sphere is halved? Our teacher said the flux decreases and the filed increases. But here: A spherical gaussian surface surrounds a point charge $q$.
Why is the electric field not affected by outside charges?
Electric field at any point is affected by all the charges in the universe. For a closed surface, the total flux through it is independent of charge outside the surface, but that does not mean that electric field is not affected by outside charges. In theory, why is the electric flux not affected when the radius of a Gaussian surface is doubled?