How do you push and pop elements in a stack?

How do you push and pop elements in a stack?

Algorithm:

1. Push the given elements to the stack container one by one.
2. Keep popping the elements of stack until it becomes empty, and increment the counter variable.
3. Print the counter variable.

Can two push operation to insert new data items in the given stack are possible?

push() function is used to insert new elements into the Stack and pop() function is used to remove an element from the stack. Both insertion and removal are allowed at only one end of Stack called Top.

How do you implement a stack which will support following operations in O 1 time complexity?

How to implement a stack which will support following operations in O(1) time complexity? 1) push() which adds an element to the top of stack. 2) pop() which removes an element from top of stack. 3) findMiddle() which will return middle element of the stack.

Is it possible to implement queue using stack or not if yes provide an efficient approach for it or justify your answer?

We can implement Queue using two Stacks. Two Stacks taken together can help us to get all the operations as supported by Queue. All the use-cases of queue can be achieved by using two stacks.

How do you push into a stack?

Stack push() Method in Java push(E element) method is used to push an element into the Stack. The element gets pushed onto the top of the Stack. Parameters: The method accepts one parameter element of type Stack and refers to the element to be pushed into the stack. Return Value: The method returns the argument passed.

What is push and pop operator stack?

In computer science, a stack is an abstract data type that serves as a collection of elements, with two main principal operations: Push, which adds an element to the collection, and. Pop, which removes the most recently added element that was not yet removed.

What is stack explain operations of stack?

How do you implement a stack in CPP?

C++ Program to Implement Stack using array

1. Push – This adds a data value to the top of the stack.
2. Pop – This removes the data value on top of the stack.
3. Peek – This returns the top data value of the stack.

How do you implement 3 stacks in an array?

You could:

1. Define two stacks beginning at the array endpoints and growing in opposite directions.
2. Define the third stack as starting in the middle and growing in any direction you want.

Which stack method looks at the top element?

peek()
Peek at Top Element of Stack The Java Stack class has a method called peek() which enables you to see what the top element on the Stack is, without popping off the element. Here is an example of peeking at the top of a Java Stack : Stack stack = new Stack(); stack. push(“1”); String topElement = stack.

How would you implement a stack using one queue?

Algorithm to Implement a stack using single queue Create the function empty(). Return true if the queue is empty else return false. push() accepts an integer value. Create an integer variable and store the size of the queue in the variable and push/insert the integer variable in the queue.

How stack and queue are implemented together?

To construct a stack using two queues (q1, q2), we need to simulate the stack operations by using queue operations:

1. push (E element) if q1 is empty, enqueue E to q1. if q1 is not empty, enqueue all elements from q1 to q2, then enqueue E to q1, and enqueue all elements from q2 back to q1.
2. pop. dequeue an element from q1.

What are push and pop operations in stack?

Push and pop are standard stack operations. The important question is, whether to use a linked list or array for implementation of stack? Please note that, we need to find and delete middle element. Deleting an element from middle is not O (1) for array.

Is it possible to use pop and Min in Stack class?

Push, pop and min should all operate in O (1) time ” My basic solution: Wouldn’t it be possible if we had a variable in stack class, that whenever we were pushing an item to stack we would check if it is smaller than our min variable. If it is assign the value to the min, if not ignore.

How to implement stack which will support following operations in O(1) time complexity?

How to implement a stack which will support following operations in O (1) time complexity? 1) push () which adds an element to the top of stack. 2) pop () which removes an element from top of stack. 3) findMiddle () which will return middle element of the stack. 4) deleteMiddle () which will delete the middle element.

How to get the minimum number of items in a specialstack?

Consider the following SpecialStack 16 –> TOP 15 29 19 18 When getMin () is called it should return 15, which is the minimum element in the current stack. If we do pop two times on stack, the stack becomes 29 –> TOP 19 18 When getMin () is called, it should return 18 which is the minimum in the current stack.