What is the sum of the present ages of father and son?
Q5: The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be: [RRB 2000] A) 12 years B) 14 years C) 18 years D) 20 years
What is the sum of present ages of A and B?
SOLUTION: The sum of present ages of A and B is 7 times the difference of their ages. 5 years hence, their total ages will be 9 times the difference of their ages. What is the present age of
What is the age difference between Ayesha’s father and mother?
Q2: Ayesha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
What is the sum of the present ages of a B C?
The present ages of A, B and C are in proportions 4:5:9. Nine years ago, sum of their ages was 45 years. Find their present ages in years
What is the sum of 4 children born at 4 years?
Sum of 4 childeren born at interval of 4 years is 36. What is the age of youngest child? Let the ages of children be x, (x+4), (x+8) and (x+12) years.
What is the sum of ages of Dan and Cary?
Then, form an equation based on these representations. Cary is 9 years older than Dan. In 7 years, the sum of their ages will equal 93. Find both of their ages now. Fred is 4 times as old as his niece, Selma. Ten years from now, he will be twice as old as she will be.
Q5. The sum of the present ages of a father and his son is 60 years. Six year ago, father’s age was five times the age of the son. After 6 years, son’s age will be?
What is the ratio of present age of mother and son?
Example 4: Ten years ago, the age of a person’s mother was three times the age of her son. Ten years hence, the mother’s age will be two times the age of her son. The ratio of their present ages will be: A) 10:19 B) 9: 5 C) 7: 4 D) 7: 3 Answer: Let the age of the son ten years ago be equal to x years.
What is an example of sum of age?
Example 1: A father and his son decide to sum their age. The sum is equal to sixty years. Six years ago the age of the father was five times the age of the son. Six years from now the son’s age will be: A) 23 years B) 19 years C) 20 years D) 22 years Answer: Suppose that the present age of the son is = x years.
What is the ratio of a father to his son?
Thus the ratio is 7:3 and the correct option is D) 7:3. Q 1: The age of a man is 24 years more than his son. In two years, the father’s age will be twice that of his son. Then the present age of his son is:
The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be. 15 years.
How old is the father in 5 years?
A man is 7 times as old as his son. In 5 years he will be 4 times as old as his son.how old is the father? x = son’s age 7x = father’s age In 5 years 7x + 5 = 4* (x+5). Simplify and solve 7x + 5 = 4x + 20 7x – 4x = 20 – 5 3x = 15 x = 15/3 = 5 years (the son’s age). ANSWER. The father is 7*5 = 35 years old. Solved.
What is the sum of ages of 5 children born 3 years?
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child? Let the ages of children be x, ( x + 3), ( x + 6), ( x + 9) and ( x + 12) years. x = 4. Age of the youngest child = x = 4 years.
What is the sum of ages of 5 children born at intervals?
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child? Let the ages of children be x, ( x + 3), ( x + 6), ( x + 9) and ( x + 12) years.
What is the product of the ages of father and son?
OMTEX CLASSES: The sum of the ages of father and his son is 42 years. The product of their ages is 185, find their ages. The sum of the ages of father and his son is 42 years. The product of their ages is 185, find their ages.
How many times older is father than his son Rohit after 8 years?
Q5: Father is aged three times more than his son Rohit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?
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The sum of the present ages of father and his son is 60 years. 6 years ago, father age was five times the age of the son. After six years son’s age will be The sum of the present ages of father and his son is 60 years. 6 years ago, father age was five times the age of the son.
What was the father’s age 6 years ago?
Originally Answered: Six years ago, father’s age was five times the age of the son and the sum of the present ages of a father and his son is 60 years. What will be son’s age after 6 years?
How do you calculate the age difference between a father and son?
Let the present ages of son and father be x and (60 – x) years respectively. ∴ Son’s age after 6 years = ( x + 6) = 20 years. Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age.
What is the age of the son after 6 years?
Lets Suppose present age of son is x and present age of father is 60 -x . x = 14. Son age after 6 years will be, (x+ 6) i.e. 20 years..
What will be the age of the father after four years?
Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are respectively,