How many ways can letters of the work ARTICLE be arranged so that vowels always occupy odd places?
ways. We can form 144 words with the letters of the word ARTICLE where vowels occupy the even places and consonants the odd places.
How can the letters of the word failure be configured while the consonants remain only in odd places?
here are seven letters in the word ‘FAILURE’ out of which the consonants are- F, L and R. And the vowels are A,E,I and U. There are total 4 odd positions (1st, 3rd, 5th and 7th) and 3 even positions (2nd, 4th and 6th) to fill. The constraint is that consonants may occupy only an odd position.
How many ways word determination can be arranged in such that a way that vowels occupy only odd position?
= 6. Total number of ways = (6 x 6) = 36.
How many words can be formed so that the vowels occupy the even places?
The number of words that can be formed out of the letters of the word ARTICLE so that vowels occupy even places is 574 b.
How many ways can the letters of the word corporation be arranged so that vowels always occupy even places?
= 360 ways. Hence, total arrangements will be 360 x 20 = 7200.
How many ways can the letters of the word friend be arranged so that the vowels come together?
120 ways. So total no of words = Answer to the problem = 4*6*120=2880 words. Consider EIIOBLMPSS. This is one such arrangement.
How many ways can the letters of the word failure be arranged so that the consonants may occupy only odd positions a 576?
Answer is 576. There are seven letters in the word ‘FAILURE’ out of which the consonants are- F, L and R. And the vowels are A,E,I and U. There are total 4 odd positions (1st, 3rd, 5th and 7th) and 3 even positions (2nd, 4th and 6th) to fill.
How many ways can be letters of the word failure be arranged so that the consonants may occupy only Oddplaces?
Consonants can be arranged in these 4 odd places in 4P3 ways.
How many different way can you arrange the letters in books so that the vowels are together?
We have to arrange these letters such that vowels come together. To solve with this constraints we assume the letters E,A and I as one unit. = 720. Hence in 720 different ways the letters of the word ‘LEADING’ can be arranged such that vowels always comes together.
How many words of the letter of the word persona can be formed so that vowels are always together *?
Number of words having all vowels together =(6×3)=18.
How do you arrange the vowels in the word machine?
There are 3 vowels in the word machine, a, i and e. The 3 letters may be arranged in 4 positions,1,3, 5 and 7, since machine has 7 letters in it. So take the first vowel, a, and that can be arranged in 4 ways, in 4 different position. So after the first letter was placed, the next one one can be placed in 3 different positions.
How many ways can vowels be arranged among themselves?
The vowels (OIA) can be arranged among themselves in 3! = 6 ways. Therefore Required number of ways = (120 x 6) = 720.
How do you calculate the number of vowels in a word?
First, put all of the vowels together – so that’s AEAI. Four letters in total, but two As, so there are 4! 2! 1! 1! = 4 ∗ 3 ∗ 2 ∗ 1 2 ∗ 1 = 12 ways these vowels can be arranged. Next, treat the block of vowels like a single letter, let’s just say V for vowel.
How many ways can 6 letters be arranged in 4 ways?
So total letter are 6. 6 letters can be arranged in 6! ways = 720 ways Vowels can be arranged in themselves in 4! ways = 24 ways Required number of ways = 720*24 = 17280