How many grams of NaClO3 were decomposed?
76.68 grams of sodium chlorate are decomposed (2NaClO3->2NaCl +302)
How many grams of NaCl are produced when 30.0 grams of O2 are produced?
How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 —> 2 NaCl + 3 O2 | Socratic.
How many grams can be produced from moles?
Multiply the resulting number by the number of grams per mole of product to find the mass of product able to be produced by the given amount of reactant. There are 2.1749 moles of NaCl and one mole equals 58.243 grams. 2.1749 × 58.243 = 126.67, so the 50.000 g of Na used in the reaction can create 126.67 g of NaCl.
What is the mass of NaClO3?
106.44 g/mol
Sodium chlorate/Molar mass
What mass of O2 is generated?
Each O weights 16 g/mol; O2 has two atoms, thus the molar mass would be 32 g/mol. 0.122399021 mol O2 *(32 g/mol O2) (mol O2 cancels out in the numerator and in the denominator, yielding 3.91679. In the question the mass has two significant figures; thus the mass of O2 released would be 4.0 g (two significant figures).
What is the name for NaClO3?
Sodium chlorate
Sodium chlorate/IUPAC ID
Sodium chlorate is an inorganic compound with the chemical formula NaClO3. It is a white crystalline powder that is readily soluble in water. It is hygroscopic. It decomposes above 300 °C to release oxygen and leaves sodium chloride.
How many moles of O2 can be produced by letting 12.0 mol of KClO3 react in the following equation?
How many moles of O2 can be produced by letting 12.00 moles of KClO3 react? The KClO3 / O2 molar ratio is 2/3. 2 mol KClO3 / 3 mol. O2 = 12.00 mol KClO3 / x = 18.00 mol.
Which statement is true if 12 mol of CO and 12 mol of Fe2O3 are allowed to react?
Which statement is true if 12 mol CO and 12 mol Fe2O3 are allowed to react? The limiting reagent is Fe2O3 and 24 mol Fe will be formed. The limiting reagent is CO and 3.0 mol CO2 will be formed.
How many moles of O2 can be produced from 12 moles KClO3?
How many moles are in 12.0 grams of O2?
0.375 moles
Therefore, 12 g of oxygen gas has 0.375 moles.
What is the product of NaClO3?
Sodium chlorate is an inorganic compound with the chemical formula NaClO3. It is a white crystalline powder that is readily soluble in water. It is hygroscopic….Sodium chlorate.
| Names | |
|---|---|
| Melting point | 248–261 °C (478–502 °F; 521–534 K) |
| Boiling point | 300–400 °C (572–752 °F; 573–673 K) decomposes |
What mass of NaClO3 is needed to produce 29g O2?
64 g NaClO3 are needed to produce 29 g O2 .
What is the mass of 12 moles of NaClO3?
Since you found the number of moles (n) and molar mass (M), you can now find out the mass of substance. The mass of O2 is [18 moles × 32 g/mol] = 576 grams. Overall, 12 moles of NaClO3 will produce 576 grams of O2.
What is the molar ratio between NaClO3 and O2?
From the chemical equation the coefficient in front of NaClO3 is 2 this tells you that there are 2 moles of NaClO3 and the coefficient of O2 is 3 so there are 3 moles of O2 so the molar ratio between NaClO3 and O2 is 2:3. Since 2moles of NaClO3 produces 3moles of O2 the question is how many moles of O2 will be produced by 12 moles of NaClO3.
How much HCl is added to Na2CO3?
1) 200 mL of 2mol/dm³ of HCl is added to 100 mL of 2mol/dm³ of Na2CO3. 2) 50mL of 2mol/dm³ of HCl is added to 100 mL of 2mol/dm³ of Na2CO3. 3) 100 mL of 2mol/dm³ of HCl is added to 25 mL of 2mol/dm³ of Na2CO3.
What is the molar mass of O2 and N ACL?
We have 80.0 grams of Oxygen and we want grams of Sodium Chloride. We need the molar mass ( gf m) of O2 and N aCl. We need the mole ratio between O2: N aCl 3:2. This comes from the coefficients of the balanced chemical equation.