How do you find the maximum height of a ball thrown up at a given time?
We know the value of g in SI is 9.8 m/second square. So just for example, if a ball is thrown vertically upwards with 98 m/s velocity, then to reach the maximum height it will take = 98/9.8 =10 seconds.
How high will a ball reach if it’s thrown straight up in the air with an initial velocity of 10 m s?
where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time. where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time. So, the ball reaches a height of 5.1m and it takes 1.02s to reach that height.
When a ball thrown straight upwards reached the maximum height of its path What would you infer about its velocity and acceleration?
The velocity and acceleration of a ball thrown upward at it’s maximum height has a velocity of zero (0) and an acceleration of “g”, the gravitational acceleration of the Earth’s pull.
When a ball is thrown vertically upwards at the maximum height * 1 point?
Answer: option d is correct.. even though at maximum height the velocity is zero , still there is acceleration bcoz even then earth is pulling it and exerting a force on it , and acceleration depends on force which comes from Newton’s second law of motion..
What is the maximum height above the ground reached by the ball?
Question: A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. At its maximum height, the speed of the ball is: Answer: 0 m/s….Objects Launched Upward.
| Variable | Value |
|---|---|
| a | -9.8 m/s2 |
| t | 0.40 s |
When a ball thrown straight upwards reaches the very top of its path?
You threw the ball straight up, so on its way up, its direction remains up. However, the ball slows down, so its speed decreases. At the very top of the ball’s motion, its speed is zero. At the very top of the ball’s motion, it is still affected by gravity, so it still has the acceleration due to gravity: 9.8 m/s2.
When a ball thrown straight upwards reaches the maximum height of its path its?
What is the maximum height?
Maximum height of the object is the highest vertical position along its trajectory. The object is flying upwards before reaching the highest point – and it’s falling after that point. It means that at the highest point of projectile motion, the vertical velocity is equal to 0 (Vy = 0).