How do you find the average of N consecutive numbers?
Prerequisite : Sum of first n natural numbers. As discussed in previous post, sum of n natural number n(n+1)/2, we find the Average of n natural number so divide by n is n(n+1)/2*n = (n+1)/2.
What is the sum of consecutive numbers from 1 to 10?
Answer is 55. Basically, you can rewrite the sum as 1+2+3+4+5+6+7+8+9+10 = (1+10+2+9+3+8+4+7+5+6) = (11+11+11+11+11) = 11*5 = 55. Using a formula: To sum consecutive numbers from 1 to n (that is 1,2,3,….,n-1,n) : a simple formula exists: n(n+1)/2. Example: here n=10, therefore n(n+1)/2 = 10(10+1)/2 = 11*5 = 55.
What is the average of 7 consecutive numbers?
The average of 7 consecutive numbers is n. If the next two numbers are included, the average will The average of 7 consecutive numbers is n implies that the 4th term is equal to n. Now if we include next two terms then the average of 9 terms will be the 5th term.
How do you find the median and mean of a series?
For example, in the sequence 3, 4, 5, 6, 7, 8, 9, the middle number is 6. It has three numbers to the left of it, and three numbers to the right of it. So, in this series of numbers, 6 is both the mean and the median. Average the middle numbers of a series with an even number of terms.
How do you find the average of five numbers?
You can prove this by setting a equal to c-4, b = c-2, d= c+2, and e= c+4. Add those four numbers together with c, and the sum of the five numbers is 5c. Divide that sum by 5 to get the average of the five numbers, which is c.
What is the 5th term of 7 consecutive numbers?
If the next two numbers are included, the average will The average of 7 consecutive numbers is n implies that the 4th term is equal to n. Now if we include next two terms then the average of 9 terms will be the 5th term. Now as the terms are consecutive, so the 5th term will be n + 1.