Can infrared cause photoelectric effect?
Thus, the shorter the wavelength the more energetic the photon. Einstein’s explanation of the photoelectric effect helped with the development of quantum theory, the description of matter and energy in the universe. This energy applies not only to light but also to x rays and gamma rays.
Why does red light not produce the photoelectric effect?
The photoelectric effect is a phenomenon that occurs when light shined onto a metal surface causes the ejection of electrons from that metal. Low frequency light (red) is unable to cause ejection of electrons from the metal surface. At or above the threshold frequency (green) electrons are ejected.
Why will violet light cause the photoelectric effect but red light won t?
As frequency of violet light is more that of blue light, hence violet light will eject photoelectrons. But the frequency of red light being less than the blue light, can not eject photoelectron from the given surface.
What light causes the photoelectric effect?
ultraviolet light
The type of light that is needed to cause the photoelectric effect is any light that has enough energy (photon energy) to facilitate the ejection of electrons from a metal. In most cases, it is the ultraviolet light.
What are the laws of photoelectric effect?
1) The emission of electrons from the surface stops after a certain frequency known as the threshold frequency. 2) The number of electrons that are emitted from the surface is directly proportional to the intensity of the incident light.
Is Visible light the only type of EM radiation that can cause the photoelectric effect?
No. The photoelectric effect just requires that the incident photon energy be greater than the work function of the material.
Why photoelectric effect Cannot be explained by the classical physics?
The photoelectric effect has three important characteristics that cannot be explained by classical physics: (1) the absence of a lag time, (2) the independence of the kinetic energy of photoelectrons on the intensity of incident radiation, and (3) the presence of a cut-off frequency.
Does red light show photoelectric effect?
Red light does not eject photoelectrons (even if it is very bright). Green light does eject photoelectrons (even if it is very dim). Blue light ejects photoelectrons with more energy than green light (even if it is very dim).
Why does violet light eject electrons from certain photosensitive surface where is red light has no effect on the surface?
Why does blue light eject electrons from a certain photosensitive surface, whereas red light has no effect on that surface? Blue light has a higher frequency and therefore a higher energy than red light and can therefore eject electrons from a metal that red light cannot.
What is photoelectric effect give any two law of photoelectric effect?
(i) There is a definite cut off value of frequency below which electrons cannot be ejected by any substance. (ii) Number of emitted electrons are directly proportional to the intensity of light incident. (iii) Kinetic energy of emitted electrons depends on the frequency of incident light on substance.
What type of electromagnetic radiation is used in photoelectric effect?
ultraviolet radiation
The photoelectric effect is the emission of electrons from matter upon the absorption of electromagnetic radiation, such as ultraviolet radiation or x-rays.
Why is the photoelectric effect not observed at the cut-off frequency?
Therefore, when incident radiation has a frequency below the cut-off frequency, the photoelectric effect is not observed. Because frequency f and wavelength of electromagnetic waves are related by the fundamental relation (where is the speed of light in vacuum), the cut-off frequency has its corresponding cut-off wavelength
Why does the photoelectric effect not occur when red light strikes metal?
The photoelectric effect does not occur when the red light strikes the metallic surface because the frequency of red light is lower than the threshold frequency of the metal. The photoelectric effect occurs when green light strikes the metallic surface and photoelectrons are emitted.
What is the relationship between light intensity and photoelectric effect?
The light intensity corresponds to the number of photons arriving at the metal surface per unit time. Even at very low light intensities, the photoelectric effect still occurs because the interaction is between one electron and one photon.
How does the photoelectric effect transfer energy from a photon?
In the photoelectric effect, photons arrive at the metal surface and each photon gives away all of its energy to only one electron on the metal surface. This transfer of energy from photon to electron is of the “all or nothing” type, and there are no fractional transfers in which a photon would lose only part of its energy and survive.