What is the probability that if she pulls two marbles with replacement they are red and then blue?
You randomly pick one, replace it (put it back), and then randomly pick another one. There are 16 possible outcomes: 1–1, 1–2, 1–3, 1–4, 2–1, 2–2, ……. So, Red/Blue is 4/16 or 25\%.
What is the probability of selecting two red marbles without replacement?
Find The Probability Of An Outcome : Example Question #2 In a bowl containing 10 marbles, 5 are blue and 5 are pink. If 2 marbles are picked randomly, what is the probability that the 2 marbles will not both be pink?
What is the probability of picking a blue marble?
There are 6+3+7 = 16 marbles in the bag, and 16 choose 1 = 16 ways to choose a marble out of the bag. Out of those 16 ways, three of them will result in a blue marble. Thus, the probability is 3/16.
What is the probability that it is a red marbles?
The probability that the marble is red is 0.5.
How many marbles are in a box of marbles?
Ex 15.1, 9 A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red?
What is the value of P (marble taken out is not green)?
P (marble taken out is not green) = P (marble taken out is white) + P (marble taken out is red) = 8/17 + 5/17 = 13/17 Ex 15.1, 9 (Method 2) A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random.
What is the probability of drawing a red marble?
To find the probability of drawing one red marble, you take the total number of red marbles and divide it by the total number of available marbles. So we have 7 red marbles and 13 total marbles (7 red + 5 blue + 1 green). Thus the probability of drawing 1 red marble is 7/13.
How many green marbles are in a sack of marbles?
A sack of marbles contains 9 red, 7 green, and 5 blue marbles. If we pull five marbles without replacement, what is the probability that exactly one is green? Ways of randomly pulling 5 marbles from among 21 randomly displaced marbles, without replacement, = 21!/ (16!) (5!) = 20,349.