What is the equation of a circle with center and radius 6?
So, if the center is (0,0) and the radius is 6, an equation of the circle is: (x-0)2 + (y-0)2 = 62.
How do you write the equation of a circle in center radius form given its radius if the center is at the origin?
The equation of a circle written in the form (x−h)2+(y−k)2=r2 where (h,k) is the center and r is the radius. The circle centered at the origin with radius 1; its equation is x2+y2=1.
How do you find the equation of a circle with the center and radius endpoint?
Explanation: The equation of a circle is (x−h)2+(y−k)2=r2 , where (h,k) is the center and r is the radius. If the center is at (−3,0) and the endpoint of the radius is at (3,0) , then the length of the radius is the distance between the two points, which is 3−(−3)=6 .
How do you write the equation of a circle in the center radius form?
A common form to write the equation of a circle in is the center-radius form. The center-radius form is: (x−h)2+(y−k)2=r2 Here, the center point is denoted by (h,k) and r is the radius of the circle.
Which is the equation of a circle with center at 3 and a radius of 6 units?
Answer: The equation of the circle, can be given as (x + 3)2 + (y + 5)2 = 36. Explanation: Given, center coordinates = (-3, -5) and radius = 6 units.
What is the equation for a circle of radius 12 centered at the origin?
The equation of a circle, centered at the origin, is x2+y2=r2, where r is the radius and (x, y) is any point on the circle.
How do you write in center radius form?
The technique of completing the square is used to turn a quadratic into the sum of a squared binomial and a number: (x – a)2 + b. The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being “r”.
What is center radius form of a circle?
The center-radius form of the equation of a circle is: (x−h)2+(y−k)2=r2.
Which is an equation of a circle with center 2 and radius 3?
Radius, r = 3 units. We have to write the equation of the circle. Therefore, the equation of the circle is (x – 2)2 + (y – 1)2 = 9.
What is the equation of a circle whose center is 3/5 and whose radius is 2 cm?
The equation of a circle with the center (3,5) and radius = 2 cm is (x – 3)2 + (y – 5)2 = 4.
What is the center radius equation for a circle?
CENTER-RADIUS EQUATION: Let the center be (h, k) and the radius be r. ( x − h) 2 + ( y − k) 2 = r 2. Let’s use the center-radius equation in some examples: Example 1: What is the center-radius equation of the circle with a diameter of 12 and a center at (-2, 5) Step 1: Identify the center coordinates and the radius.
What is the standard form of the equation of a circle?
Standard form equation of a circle : (x – h) 2 + (y – k) 2 = r 2 Here (h, k) stands for center of the circle and “r” stands for radius. If the center of the circle is at origin, the equation will become
How to write the equation for a circle centered at the origin?
Write the equation for a circle centered at the origin with a diameter of 6. Step 1: Identify the given center of the circle, and define values for h and k as the x and y -coordinates of the center point, respectively. If the center of the circle is at the origin, that means its coordinates are (0, 0).
How do you find the general form of a circle?
Step 1: Identify the given center of the circle, and define values for h and k as the x and y -coordinates of the center point, respectively. Step 2: Identify the diameter of the circle, and convert it to a radius by dividing it by 2. Step 3: Fill in the equation for the general form of a circle.