How many ways can you divide 12 people into 3 groups?
5775 different ways
Summary: You can split 12 people into 3 teams of 4 in 5775 different ways.
How many ways can 12 students be assigned to 3 equal groups of four the order of groups does not matter?
of ways are 12C4*8C4*1/3! i.e. 495*70*1 /6=5775 ways. Divided by 3! because order of group does not matter.
How many ways can you divide 15?
15 people can be divided into 3 groups of 4 each in (15C5)*(10C5)*(5C5) = 15!/(5!* 5!* 5!) = 756756 ways.
How many ways can 15 students join 5 different clubs?
Hence the Answer is 171 990 Ways.
How many ways can you split 10 people into 2 teams?
Hence, the number of ways 10 students can be divided into 2 groups with at least 1 person per group is 10+45+120+210+252 = 637 ways.
How many ways could a class of 18 students divide into groups of 3 students each?
= 18*17*16*15!/(3*2*1*15!) = 6*17*8 = 816 ways to choose 3 students from a class of 18 students.
How do you write 15 divided by 3?
Using a calculator, if you typed in 15 divided by 3, you’d get 5. You could also express 15/3 as a mixed fraction: 5 0/3. If you look at the mixed fraction 5 0/3, you’ll see that the numerator is the same as the remainder (0), the denominator is our original divisor (3), and the whole number is our final answer (5).
How many ways can 5 people be divided into three groups?
Here, the 5 people either be put in one group of 3 people then two groups with 1 person, or two groups with 2 people then one group of 1 person. Hence, 5 people can be divided into three groups in 25 ways. Was this answer helpful?
How many distinct permutations of 5 are there?
Each group of 5 is unique and there is no over-counting by a factor of 3!. If say, there were to be 3 groups of 4, 5 and 6, the number of distinct permutations would be = (3!)* [15!/ (4!) (5!) (6!)] = 3,783,780. In this case there is a 3! multiplier to account for 3 different sized groups and attendant additional permutations.
How many ways can you arrange students in 3 equal groups?
There are 15! ways to line up students in a line. However, in any particular line up, the order of the students in each group does not matter. Thus, for each line up, we have 5! 5! 5! ways of arranging the students in each group. Therefore, the number of ways to arrange students in 3 equal groups is:
How to prove a group of two is divisible by 3?
The number is divisible by 3 The number leaves a remainder of 1, when divided by 3 The number leaves a remainder of 2, when divided by 3 Now, for groups of two being divisible by 3, either both number have to belong to category 1 (both are divisible by 3), or one number should leave a remainder 1, and the other a remainder 2.