How many ways are there to arrange 5 boys and 5 girls around the table such that no two boys are next to each other?
= 2! × (5!) Total number of ways in which no girls are together = Total number of arrangements – Number of arrangements in which all the girls are together. 5 boys and 5 girls total number of arrangements of = 10P10 = 10!
How many ways can 4 girls and 4 boys be seated alternately in a row of 8 seats?
2*24*24=1,152 total arrangements to seat 4 boys and 4 girls, alternating boys and girls, into 8 seats.
How many ways can five girls?
The girls can be arranged in a row in 5! ways = 120 ways.
How many ways can you arrange 4 boys 4 girls?
There are 4 boys and 4 girls; they can be permuted among themselves in 8! = 40320 ways.
How many ways can 5 boys and 5 girls be seated?
The total of ways for seating these 5 boys and 5 girls with he constraint of having 3 particular girls, randomly chosen from among 5 girls, to sit together = 10* (3!) (7!) = 302,400. How many ways can 5 boys and 5 girls be seated at a round table if 3 particular girls must not sit together?
How many girls have to sit in the gap between 5 boys?
For boys and girls to occupy alternate positions, 5 girls has to sit in the gap between the 5 boys. What does Google know about me? You may know that Google is tracking you, but most people don’t realize the extent of it.
How many ways can you rearrange 4 boys and 5 girls?
For the third seat there are 4 possible girls to be seated there. For the fourth seat we have 3 possible boys who can be seated there. This goes on and so we see that there are: 5*4*4*3*3*2*2*1*1=2880 ways of rearranging this particular group of 4 boys and 5 girls so that they are alternate.
How many boys and Girls can you have in a row?
You can either start with a boy or with a girl, BGBGBGBGBG or GBGBGBGBGB, those are the only two ways to arrange boys and girls, alternating, in a row. So the answer is either 2, if you don’t care WHICH boy sits where (and WHICH girl sits where), or it’s 2*5!*5!, which is 28800.