What is the probability that a randomly selected three digit number is divisible by 5?
180/900
1 the total number of integers from 100 through 999 is 999 – 100 + 1 = 900. By part (a), 180 of these are divisible by 5. Hence the probability that a randomly chosen three-digit integer is divisible by 5 is 180/900 = 1/5.
What is the probability that a 3 digit number is divisible by 7?
100\%. 777 for example. Now maybe you meant what is the probability that a randomly select 3 digit number is exactly divisible by 7. There are 899 numbers in the range 100 to 999.
How many 3 digit numbers are divisible by 7 or?
128 three digit numbers
Hence, 128 three digit numbers are divisible by 7.
How many of the three digit numbers are divisible by 5?
180 three digit numbers
Hence there are 180 three digit numbers divisible by 5.
What is the probability of getting a 3 digit number divisible by 3?
We have 900 three digit numbers from 100 to 999. 300 of them 102,105,…,999 are divisible by 3. So, the answer to the first question is 300/900 = 1/3.
What is the probability that a three digit number?
The probability of forming a three-digit numbers with the same digits, when three-digit numbers are formed out of the digits 0, 2, 4, 6, 8, is. Hence, the probability that the three-digit numbers with same digit = 4/100 = 1/25.
How many 3 digit number which are divisible by 3?
The three digit natural numbers start from 100 and ends with 999 . The first three-digit number which is divisible by 3 is 102 . The last three-digit number which is divisible by 3 is 999 . The number of three-digit numbers divisible by 3 are 3999 − 3102 + 1 = 333 − 34 + 1 = 300 .
How many three digit numbers are there which are divisible by 3?
300
The three digit natural numbers start from 100 and ends with 999 . The first three-digit number which is divisible by 3 is 102 . The last three-digit number which is divisible by 3 is 999 . The number of three-digit numbers divisible by 3 are 3999 − 3102 + 1 = 333 − 34 + 1 = 300 .
Why is there no divisibility rule for 7?
The divisibility rule of 7 states that for a number to be divisible by 7, the last digit of the given number should be multiplied by 2 and then subtracted with the rest of the number leaving the last digit. If the difference is 0 or a multiple of 7, then it is divisible by 7.
How many three digit numbers are divisible by 5 can be formed using any of the digits from 0 to 9?
Hence any of 8 digits (1,2,3,4,6,7,8,9) can be placed at hundreds place….Permutation and Combination #57.
| 57. How many three digit numbers divisible by 5 can be formed using any of the digits from 0 to 9 such that none of the digits can be repeated? | |
|---|---|
| A. 136 | B. 124 |
| C. 112 | D. 108 |
How many three digit no’s are divisible by 3 or 5?
300 3-digit numbers divisible by 3.
How many 3 digit numbers can be formed which are divisible by 3?
Therefore there are 300 3digit numbers are divisible by 3.
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