What is the force when body of mass 5 kg has an acceleration of 2 m s2?
Hence, the force acting on a body of mass 5 Kg and accelerating with an acceleration of 2 ms-2 is F = 10N.
What force is necessary to accelerate a 5kg mass to 10m S in 5 sec?
So the answer is Fnet=50N .
What will be the force applied to a 5kg box which was pushed with an acceleration of 2m s2?
If you are asking for the net force in the direction of acceleration , the net force has a magnitude ma =5kg x 2m/s^2 =10N. Newtons second law of motion relates acceleration to the net force (the resultant of a number of forces).
What is the acceleration of 5 kg mass?
Acceleration on 5kg block = 2 x 5 = 10 m/s².
What is the force applied on a body with 5 kg of mass and an acceleration of 7m s2?
What is the force applied on a body with 5 kg of mass and an acceleration of 7 m/s2? Explanation: According to the second law of motion, the force on a body is equal to the rate change of its momentum. On simplifying we get, F = ma. Therefore, Force = 5 x 7 = 35 N.
What is the velocity of a 5.5 kg object that has a momentum of 550 kg * m s?
How much momentum does a 25 kg mass moving at 25 m/s have? How much momentum does a stationary 5500 kg mass have? What is the velocity of a 5.5 kg object that has a momentum of 550 kg·m/s? walking 0.20 m/s.
What is the acceleration of a 5 kg mass pushed by a 10N force?
Here the force is 10N and the mass is 5 kg. Dividing both sides by 5kg, we get a = 2 m/s^2.
What is the force of 5kg?
The gravitational force on a body of mass 5 kg at the surface of the earth is 50 N.
What is the acceleration of a 5 kg object that is pushed by a force of 10 Newtons?
F = ma (magnitude-wise) so if the force applied on the body is 10N, 10 N = 5 kg × a m/s², ‘a’ being the acceleration of the body, a = F/m = 10÷5 = 2 m/s².
What is the force of a box that has a mass of 5 kg that is pushed 2 m s?
Fnet can be found using Fnet = m • a = (5 kg) • (2 m/s/s) = 10 N, right. Since there is no vertical acceleration, the normal force equals the gravity force. Once Fnorm is known, Ffrict can be found using Ffrict = “mu” • Fnorm = (0.1) • (49 N) = 4.9 N.
What is the force applied on a body with 5 kg of mass and an acceleration of?
Explanation: According to the second law of motion, the force on a body is equal to the rate change of its momentum. On simplifying we get, F = ma. Therefore, Force = 5 x 7 = 35 N.
What is the speed of a block of mass 5kg?
A block of mass 5kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5N acts on it for 4 secs. What will be the distance of the block from the point where the forces started acting?
What is the force required to stop a moving block?
If constant force is brought to the block, acceleration would be also a constant, because of the formula “F = ma”, Force = mass × acceleration. F = ma = 5 kg × 3750 m/s² = 18750 N (N = kg⋅m/s²). You need constant force of 18750 N to stop the block. 8 clever moves when you have $1,000 in the bank.
How much force is required to accelerate 5kg from 3kg to zero?
So to accelerate 5kg from 3 to Zero m/s in 0.0008 seconds would be 15 X 1250 which is => 18750N or 18.75kN or almost 2 tonnes. Your question lacks essential conditions. There is no answer if you don’t mention about ‘constant’ force.
What is the velocity of the conveyor belt when the boxes fall?
Boxes are transported by a conveyor belt with a velocity v0 to a fixed incline at A where they slide and eventually fall off at B. Knowing that k0.40, determine the velocity of the conveyor belt if the boxes leave the incline at B with a velocity of 8 ft/s.