How many ways can 4 balls of the same colour be selected?
Balls of same colour are non-identical. Finally chosen 4 balls must contain at least one red, one white and one black ball each. This process can occur in (2C2)*(3C1)*(4C1) = 1*3*4 = 12 ways. This process can occur in (2C1)*(3C2)*(4C1) = 2*3*4 = 24 ways.
How many ways ten balls can be picked from a pile of red blue and white balls?
Now, 10 balls can be selected from these 47 balls in ways. …
How many ways can you choose 5 balls so that 4 of them are the same colour?
You have three choices of yellow balls, four of black, and so on. The choices are independent, so multiply them. There are 5 balls and 5 colors, therefore we are picking exactly one of each color. The number of ways to do this is 3×4×6×2×6=864.
What are the possible ways in which you can select 3 balls out of 6 balls?
of ways to choose 3 balls as follows: 28+21+15+10+6+3+1= 84.
How many ways of selecting two balls of the same Colour from 3 red and 4 black balls are there?
in 9 Ways two balls of the same colour can be selected out of 4 distinct black and 3 distinct white balls.
How many ways Select all method?
Method 1 of 4: Windows. Press Control + A on the keyboard. This fast keyboard shortcut will select all selectable items on the active window or page.
How many different ways are there for the 6 balls to be selected?
Using the combinations formula, the first case would be 5C2*4C2 = 10^6 = 60.
How many ways can you pick 5 ball?
possible ways. Obviously if you want also to take into account the order of drawing, you have to multiply by 5! =120.
How many ways can you pick 3 out of 5?
10 possible combinations
So 5 choose 3 = 10 possible combinations.
How many ways can you select 3 balls out of 9?
Ways of selecting 3 balls out of 9 balls if at least one black ball is to be selected. A box contains two white, three black, and four red balls. In how many ways can three balls be drawn from the box if at least one black ball is to be included in the draw. The answer given is 64.
How many ways can the 4 red balls be arranged?
The 4 red balls an be arranged in 4! ways. The 4 red balls leave 3 gaps between them and the two extreme sides i.e. 5 places to insert the 3 yellow and the 2 green balls. These can be arranged in 5! ways.
How many possible combinations can you make with 12 different balls?
If you choose only one element r = 1 at once from that set, the number of combinations will be 12 – because there are 12 different balls. However, if you choose r = 12 elements, there’ll be only 1 possible combination that includes every ball. Try it by yourself with the n choose r calculator!
What is the total number of arrangements that no two balls?
Out of the 5 available spaces, 3 spaces can be selected in 5C3 ways to insert the yellow balls. In the remaining 2 places, the green balls can be placed in 1 way. Hence total number of arrangements such that no two balls of the same colour are next to each other = 5C3 = 10.
How many different numbers are there in a set of balls?
So let’s assume that in any arrangement we are not able to distinguish the balls having the same colour, so only different orders of the colours involved are counted. If we number these balls we have 12 different numbers, 3 of which belong to the white balls, 4 belong to the blue balls and the final 5 belong to the red balls.