How many grams of water are made when 8.0 grams of oxygen reacts with hydrogen gas 2h2 O2 2h2o?
So 2.252 g of water will be formed.
How many grams of water are made when 8.0 grams of oxygen reacts with hydrogen gas?
2 Answers. ≈70 g H2O will produced from 8 g H2 .
How many grams of hydrogen and oxygen are in 100 grams of water?
Hydrogen’s \% is therefore 2g/18g x 100 =11.1\%; oxygen’s is 16g/18g x 100 = 89.9\%; now, out of 100g of water, that makes 89.9g of oxygen and 11.1 g of hydrogen.
What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen in moles?
The molecular masses of hydrogen, oxygen and water are 2 g/mole, 32 g/mole and 18 g/mole respectively. 2×2=4 g of hydrogen reacts with 1×32=32 g of oxygen to form 2×18=36 g of water. =9 g of water. 9 grams of water can be produced when 8 g of hydrogen reacts with 8 g oxygen.
What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen *?
What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen? Clarification: The chemical equation of water formation is 2H2 + O2 → 2H2O. Though we have 8g of hydrogen, here oxygen is the limiting reagent. So the only 4g of hydrogen can be used to produce water i.e. 36g of water.
Is 75 gram of water is decomposed how many grams of oxygen and hydrogen are obtained?
If we decompose 100 grams of pure water by passing electricity through it then 11 grams of hydrogen and 89 grams of oxygen obtained. This experiment shows that water always consists of the same two elements hydrogen and oxygen combine together in the same constant proportion of 11: 89 or 1:8 by mass.
How many grams of water are produced when 100 g oxygen is reacted with 100g of acetylene?
So the answer is 38.88 g of water.
How many grams of water will be produced if you react 32.6 LG of hydrogen with excess of oxygen?
36 g of water will be formed.
What is the amount of water produced when 4g of hydrogen is reacted with 32g of Dioxygen?
Explanation: 4g Of hydrogen reacts with 32g of oxygen to produce 36g of water.
What is the limiting reagent if 2 grams of H2 react with 8 grams of O2 to form water?
Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product. By Stoichiometry of the reaction: 1 mole of oxygen gas produces 2 moles of water molecule.
What is the amount of water produced when 8g of hydrogen is reacted with 32g of oxygen a 2moles B 1mole?
What is the mass of water formed when 80G H2 reacts with O2?
Formation of water by 5 molecule of H2 and 2.5 molecule of O2 therefore 5 molecule of H2 is 10gm and 2.5 molecule of O2 is 80gm form by summation is 90gm of H2O molecule. Originally Answered: 80g Of H2 are reacted with 80g of O2 to form water find out mass of water obtained which substance is limiting reagent?
How many grams of hydrogen are needed to make 9g of water?
Hence, 4g Hydrogen Reacts With 32g Oxygen To Form 36g Of Water ,It Means That For Each 1g Hydrogen 8g Oxygen Is Needed To Make 9g Water . We Have Given 80g Of Each Hydrogen And Oxygen .
How much oxygen is needed to make 720g of water?
We Need 640g Oxygen For 80g Hydrogen To Make 720g Water , But We Only Have 80g Of Oxygen So In This Reaction Oxygen (O2) Will Act As A Limiting Reagent . 80g Oxygen (O2) Forms 90g Water (H2O). Intresting Question …
How do you calculate the percentage of hydrogen and oxygen in water?
You need to determine the percent by mass of both hydrogen and oxygen in water. Since the formula for water is H2O, take the masses off of the periodic table: 2x1g for hydrogen (because there are 2 H in the formula); 1x 16g for oxygen (because there is 1 O in the formula), added together for a total of 18g.