How many different two digit numbers can you form using the digits and without repetition for example is not allowed?
As we have 9 digits(i.e. 1 to 9), we can place any one of them in the first place of two digit number. Next as there is no repetition,the placed number can’t be used again. so other than that number should be placed in another position. now the required answer is 9*8=72.
How many 5 digit numbers are there that have digits 1 2 3 4 and 5 each of them exactly once?
So the answer to your question is 120 five-digit numbers.
How many two digit numbers can be generated using the digits 1 2 3 4 without repeating any digit?
Since we cannot repeat the digits, we are left with 3 digits now. The second digit can be any of these three digits….Permutation and Combination #31.
31. How many two digit numbers can be generated using the digits 1,2,3,4 without repeating any digit? | |
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A. 10 | B. 12 |
C. 4 | D. 16 |
How many two digit numbers can be formed from the digits 12345 if the digits can be repeated?
Answer Expert Verified digits can be repeated. Hence, the number of two digit even numbers that can be formed = 2 x 5 = 10.
How many 5 digit numbers can be formed using the digits 1 and 2?
The total number of 5 digit numbers that can be formed from 1,2,3 digits are 3*3*3*3*3=243. To get the result where all the digits occur atleast once ,we need to subtract the result of the cases where we dont find all the digits from the total no. of possibilties i.e 243.
How many 4 digit combinations are there using 1 9?
10,000 possible combinations
Berry analyzed passwords from previously released and exposed tables and security breaches, filtering the results to just those that were exactly four digits long [0-9]. There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
How many ways can a 4 digit number be formed?
Hence, total number of ways = 30 + 15 + 1 = 46 ways. How many 4-digit numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 which are divisible by 5 when none of the digits are repeated? A number is divisible by 5 if and only if its last digit is either 5 or 0.
How many ways can a 5-digit number be filled up?
A five-digit number cannot have 0 as the first digit on the left, which is the ten thousand place. Overall, every one of the 5 places of a 5-digit number can be filled up in ten ways, because it can have 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. So each of the five places can be similarly filled up in ten ways.
What is the total number of combinations possible with 5 numbers?
Overall, every one of the 5 places of a 5-digit number can be filled up in ten ways, because it can have 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9. So each of the five places can be similarly filled up in ten ways. Therefore, the total number of combinations possible are 10 × 10 × 10 × 10 × 10 = 1,00,000.
What is the total number of possible 3 digit numbers?
Now, as the repetition is allowed, the digits possible at B is 6. Similarly, at A, also, the number of digits possible is 6. Therefore, The total number possible 3 digit numbers = 6 × 6 × 3 = 108. 3. How many 4-letter code can be formed using the first 10 letters of the English alphabet, if no letter can be repeated?