How can you prepare 250ml 0.1 N K2Cr2O7 aqueous solution?
Standardization of 0.1 N Potassium dichromate (K2Cr2O7) Solution
- Place 40 ml of water in a 250-mL glass-stoppered conical flask.
- Add 40 mL, accurately measured, of the K2Cr2O7 solution.
- Add 3 g of potassium iodide (KI), 2 g of sodium bicarbonate (NaHCO3), and 5 mL of hydrochloric acid (HCl).
What is the normality of potassium dichromate solution taken?
The normality of potassium dichromate can vary from solution to solution. With regards to the number of equivalents of potassium dichromate per mole, for an acid-base reaction, the total number of equivalents will be 2. In redox reactions, the total number of equivalents per mole will be 6.
What is the molecular weight of K2Cr2O7?
294.185 g/mol
Potassium dichromate/Molar mass
What is the N factor of k2 cr2 o7?
6
Potassium dichromate in an acidic medium is a strong oxidizer. It means it gains electrons during redox reaction. There is overall gain of 6 electrons. That means n-factor for this reaction is 6.
How will you prepare 1 M potassium dichromate solution?
Potassium Dichromate Solution Preparation Weigh 4.9 g of potassium dichromate, previously powdered and dried in a desiccator for 4 hours. Dissolve in sufficient water to produce 1000 ml.
How do you make a 1n solution?
To make 1 N sodium chloride solution So dissolve 58.5 grams of NaCl in distilled water and makeup to one liter.
How do you prepare potassium dichromate indicator?
Potassium chromate indicator solution: (approximately 0.25 molL-1) Dissolve 1 g of K2CrO4 in 20 mL distilled water. If the seawater contains traces of solid matter such as sand or seaweed, it must be filtered before use.
What is molecular formula of K2Cr2O7?
K2Cr2O7
Potassium dichromate/Formula
How do you find the equivalent weight of K2Cr2O7?
Calculate equivalent weight of K2Cr2O7 in acidic medium. = 294 g/mol. Now, putting these values in above formula of equivalent weight: \[Equivalent{\text{ }}weight = \dfrac{{294}}{6} = 49g/eq\]. Hence, the equivalent weight of ${K_2}C{r_2}{O_7}$ in acidic medium will be 49g/eq.
What will be the equivalent weight of K2Cr2O7 in acidic medium molecular weight of K2Cr2O7 is M?
Equivalent weight = M / 6. – Hence, the answer is option (C) M/6.
How do you make a 5m HCl solution?
Take 10 mL of HCl and mixed with 90 mL of Distilled Water. (Take Water first i.e. in 90 mL of water add 10 mL HCl) it will give you 10\% v/v HCl.
How to prepare K2Cr2O7 solution?
UpFor the preparation of 0.1 N solution of K2Cr2O7 in 100 ml water,.01 gram equivalent of K2Cr2O7 dissolved in 100ml solution. For the preparation of 0.1 N solution of K2Cr2O7 in 100 ml water,.49 gram of K2Cr2O7 dissolved in 100 ml solution.
What is the molar mass of K2Cr2O7?
Molar mass of K2Cr2O7 = 294.1846 g/mol. This compound is also known as Potassium Dichromate. Convert grams K2Cr2O7 to moles or moles K2Cr2O7 to grams. Molecular weight calculation: 39.0983*2 + 51.9961*2 + 15.9994*7.
What is the colour of k2cr207?
Colour changes: K+ in K2Cr207 is a colourless ion, and dichromate (Cr2O72-) is an orange solution. SO2 is a colourless gas, so the intial solution is orange. The solution turns green because the Cr2O72- is reduced to Cr3+ which is a green ion- so the solution turns from orange to green.
How do you find the equivalent weight of potassium dicromate?
To find equivalent weight of potassium dicromate, we must go through the change of oxidation state of Cr in the reactant and product as well in acid medium . ( Cr2O7^-2→ 2 Cr^+3). Here oxidation state changed from (2×6 to 2×3, so the change is 6) the equivalent weight of K2Cr2O7 =294.18/6=49.03.