Can 6 end with digit 0 for any natural number n?
If any number ends with the digit 0 that means it should be divisible by 5. That is, if 6n ends with the digit 0, then the prime factorisation of 6n would contain the prime number 5. That means 6n will not be divisible by 5. Therefore, 6n cannot end with the digit 0 for any natural number n.
Can the number 6 power N being a natural number end with the digit 5 give reason?
For any number ending with 5 the prime factor 5 should be there in its primefactorisation (for eg: 5=5,15=3×5,25=5×5). But 6n has only 2 and 3 as prime factors.So 6n can never end with digit 5 for any natural number n.
Can you end with digit 0?
If any digit has the last digit 10 that means it divisible by 10. should be divisible by 2 and 5. is divisible by 2 but not divisible by 5. So, it can not end with 0.
Can the number 6 N?
No, because 6n = (2 × 3)n = 2n × 3n , so the only primes in the factorisation of 6n are 2 and 3, and not 5. Hence, it cannot end with the digit 5.
Can the number 8 nn being a natural number?
Answer: it is not possible because 0 is not a natural number it is a whole number…….
Can the number 6n n being a natural number and with the digit 5?
Given number is 6n, where n is the natural number ending with digit 5. So the number must be divisible by 5, if take first natural number ending with 5. So the last digit of 6n can never be 5.
Can the number 16 and N being a natural number and with the digit 0 give reason?
No it can’t end end with 0, As 6 is the last digit of 16^n, It always ends with 6.
What is the last digit of 6 power N?
Hi, This is related to concept of numbers in the unit digits place of the powers of natural number. The power of 6 any index repetition 6 i.e, (6)^any power —– the last digit is 6 only. Example: i) 6^1 = 6 ii) 6 ^2 = 36 iii)6*^3 = 216 . . . the last digit in the expansion of 6 ^100 is 6.
What is the last digit of 6 to the power of 2020?
Answer: 6to the anything give the last degit is 6.so the answer is 6.
Can the number N being a natural number end with the digit 0 give reasons?
➡For a number to end with zero, it must have 10 i.e. 2 and 5 in its prime factorisation. ➡The prime factorisation of 4 does not include 5. ➡Hence, the number 4^n cannot end with the digit zero.
Can 6N end with digit 0 for any natural number?
Check whether 6n can end with digit 0 for any natural number n. If 6n is end with zero for a natural number n, it should be divisible by 2 and 5. This means that prime factorization of 6n should contain the prime number 2 and 5. But it is not possible because 6n = 2n ∗3n so 2 & 3 is only prime in the factorization of 6n.
What is the last digit of 6^N?
As we can see, 6^n for any value of n (where n is a natural number) ends with the digit 6. It never ends with 0. this is happening because we are to put a cross after lst step of multiplication nothing is added to this number….hence for any power of 6 the result would contain 6 as its last digit
What is the prime factorization of 6N if it ends with 0?
Answer If 6n is end with zero for a natural number n, it should be divisible by 2 and 5. This means that prime factorization of 6n should contain the prime number 2 and 5. But it is not possible because 6n = 2n ∗3n so 2 & 3 is only prime in the factorization of 6n.
Is 6N divisible by 2 and 5?
If 6 n is end with zero for a natural number n, it should be divisible by 2 and 5. This means that prime factorization of 6 n should contain the prime number 2 and 5. But it is not possible because 6 n=2 n∗3 n so 2 & 3 is only prime in the factorization of 6 n.