How long in seconds does it take the stone to reach the highest point?
v(t) = 24 – 1.6t = 0 ⇒ t = 24 1.6 = 15. It takes 15 seconds to reach the highest point.
What is the maximum height that the stone will reach?
80 m.
When the stone reaches its maximum height, for a moment the velocity of the stone becomes zero at that instant and then it starts falling back towards ground. So, the maximum height to which the stone can reach is 80 m.
What maximum height a stone will reach if it is thrown upwards with a velocity of 20m sec?
∴ The Maximum height reached by the stone when it is thrown vertically thrown with a velocity of 20 m/s and g as 10 m/s² is 5m.
How long does it take to reach the maximum height?
You don’t even need to find out the height, it’s just a matter of measuring the time it takes for gravity to reduce the speed to 0. In mathematical terms, it can be considered as: If and , then . That means it takes 3.058 s for the ball to reach its maximum height.
What is the velocity of the rock when it hits the ground?
When the rock hits the ground its velocity is 7.3 m/s.
What is the velocity after t seconds?
4+2t m/s.
After t seconds, the velocity of the particle is 4+2t m/s.
When a stone is thrown vertically upwards then work done by gravitational force is?
When ball is thrown vertically upward the work done is negative and when ball becomes downward the work is positive because the is done against gravity.
When a stone is thrown vertically upwards why does it fall down after reaching a height?
When the stone travelling vertically upwards, it is experiencing the retardation due to gravity. After reaching maximum height, the stone descends with zero initial velocity, accelerated downwards due to gravity and reaches the ground after time t’.
When a cricket ball is thrown vertically upwards?
hence, 0=10+10t ⇒t=1010=1s. When a cricket ball is thrown vertically upwards, it reaches a maximum height of 5 metres.
How do you find initial height with maximum velocity?
h = v 0 y 2 2 g . h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.
How do you find initial velocity and final velocity?
Final velocity (v) of an object equals initial velocity (u) of that object plus acceleration (a) of the object times the elapsed time (t) from u to v. Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth’s gravitational force as the acceleration rate of an object.
What will be the acceleration of a rock that is thrown upward from the surface of earth?
Notice that when the rock is at its highest point (at 1.5 s), its velocity is zero, but its acceleration is still −9.80 m/s2. Its acceleration is −9.80 m/s2 for the whole trip—while it is moving up and while it is moving down.