How many possibilities are there with 12 numbers?
4,095
The number of possible combinations with a 12-digit number is 4,095.
How many 3 digit numbers can be formed from the digits 0 to 5 without repetition?
Question 8 How many different 3-digit numbers can be formed by using the digits 0, 2, 5 without repeating any digit in the number? The different 3-digit numbers which can be formed by using the digits 0, 2, 5 without repeating any digit in the number are 205, 250, 502 and 520.
How many different two digit numbers can you form using the digits and without repetition for example is not allowed?
As we have 9 digits(i.e. 1 to 9), we can place any one of them in the first place of two digit number. Next as there is no repetition,the placed number can’t be used again. so other than that number should be placed in another position. now the required answer is 9*8=72.
How many 3 digit numbers can be formed from the digits 1/2 and 3?
This is because you have space for three digits that can be chosen from the set [1,2,3]. So you can make 27 three digit different numbers .
How many different combinations can you make with 11 numbers?
See for 11 numbers there can be 9 ways for each number for 1st nine places since 0 can’t be the fist number and next two are repeated from 10 numbers hence 10!/2! So 99 combinations have 10!/2! Permutations hence total ways are 99*10!/2!
How many 3 digit numbers can be formed by using the digits 0 5 7 without repeating any digit in the number?
The possible 3-digit numbers are: 507, 705, 750, 570.
How many 3 digit numbers can be formed using the digits 0 to 9 if no digit is repeated?
Hence, the required number of numbers = 504.
How many ways can a 2-digit number be formed by using only the digits 5’9 and by each digit being used only once?
20 ways
How many ways can a 2-digit number be formed by using only the digits 5–9 and by each digit being used only once? There are 20 ways for the numbers to be formed.
How many two digit numbers can be formed from the digits 12345 if the digits can be repeated?
Answer Expert Verified digits can be repeated. Hence, the number of two digit even numbers that can be formed = 2 x 5 = 10.
How many unique 3 digit codes can be created from the 5 digits?
Since repetition of digits is allowed, we have 5 choices for each of the 3 digits of each code. Therefore, 5*5*5 = 125 such 3-digit codes are possible.
How many 3 digit number can be formed by using the digit 1 to 9?
How many digits cannot be repeated in a number system?
(I)Case I: Digits cannot be repeated:If 0 is placed in first place then it becomes a 3-digit number out of 4-places.Thus ,we can fill 1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9 in the first place. Consider the third place.We can fill any of the 8 digits.
How many possible digits are there in thousands place?
Out of these we need to make 4 digit numbers ie we have 4 places …thousands, hundreds, tens , ones In thousands place out of 10 digits 0 is to be excluded or else the number so formed turns into a 3 digit number. So, 9 possible digits in thousands place. In hundreds place, we can include 0 but already one digit has been placed in ‘thousands’
How many unchosen digits if each digit can be used only once?
0,1,2,3,4,5,6 if each digit can be used only once? There are 7 unchosen digits Choose the first digit any of 6 ways other than 0. That leaves 6 unchosen digits Choose the second digit any of 6 ways.
How many choices are there in a 4 digit number?
Suppose there are 4 boxes to be filled each with a distinct digit and it has to be of 4 digits. 4th has 7 digits that can be filled other than that are already filled in other 3 boxes. The four digit number can’t have’0′ at its thousand’s place. So, one has only 9 choices for this digit (1 through 9).