What is the probability that two balls selected at random from the bowl have the same color?
For red, RR, there is only 1 way to pull out 2 red balls, 2 choose 2 = 1. So there are 4 ways, P( 2 balls same color) = 4/15. P(Pull 2 balls with different color) = 11/15.
What do you mean by expectation of a random variable?
The expectation or expected value of a random variable is a single number that tells you a lot about the behavior of the variable. Roughly, the expectation is the average value of the random variable where each value is weighted according to its probability.
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What is the probability of last two configurations of the balls?
If the balls are placed on each box with the same probability, each configuration have probability 1 / 4, hence the probability of success (last two configurations) is 1 / 4 + 1 / 4 = 1 / 2. Suppose now we are told that the balls are indistinguishable.
How do you find the number of distinguishable boxes from two balls?
Let’s have a look at an example with N = 2 indistinguishable balls and m = 2 distinguishable boxes. So, after distributing the 2 balls into the 2 boxes, we can see one of three possible outcomes: which respects the fact that the balls are indistinquishable and the boxes are distinguishable.
What is the probability of picking a red ball out?
5) The probability of picking a red ball is 4/10 and the probability of picking a green ball is 3/10 and because the ball is put back in the box, the second green is also 3/10. So the probability is: Fig.5 Probability without replacement second ball out.
What happens if the balls are thrown on the same ball?
The answer depends on the assumed probability model. If the balls are thrown on each ball with equal probability, then it does not change anything. True, we now have only one successful configuration, but it has probability 1 / 2 (it can happen in two ways).
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