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How many grams of H2O will be produced if 88.0 g of C3H8 react with excess oxygen?

Posted on September 4, 2022 by Author

How many grams of H2O will be produced if 88.0 g of C3H8 react with excess oxygen?

Therefore, 8 mol of water is produced and since water has a mass of 18g per mole, simply multiply 18 by 8 which you might also be able to do in your head and get 144g of water.

What is the total number of liters of h2 produced at STP when 36.0 g of H2O is consumed?

The answer is 21.5 L .

What is the mole ratio of C3H8 to H2O?

Next look at the stoichiometric ratio of water to propane (C3H8), which is 4:1 based on the coefficients. That means that for every one mole of propane used, four moles of water are created. Therefore, if we need to make 0.5944 moles of H2O, we will need a quarter of that for propane, or 0.1486 moles C3H8.

Is C3H8 5o2 → 4h2o 3CO2 balanced?

There are 10 oxygens in the reactants and 10 oxygens in the product. Good again. This means that the equation is already balanced.

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How many moles of water H2O are present in 75.0 g of H2O?

FREE Expert Solution Convert the mass to moles (using molar mass). There are 4.17 mol H2O in 75 grams of water.

How many molecules of CO2 H2O c3 h8 and O2 will be present if the reaction goes to completion?

When the reaction goes to completion, we will have 1 molecule of C3H8 , 0 molecules of O2 , 6 molecules of CO2 , and 8 molecules of H2O .

What is the total number of liters of O2 measured at stp?

O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles. 1 mole of any gas at stp is 22.4 liters. 1.5625 × 22.4 = 35 liters.

How many liters of oxygen at NTP are required to burn 2.2 grams of propane?

5.6 litre o2 at stp.

How do you calculate moles of H2O from C6H12O6?

4.838 g H2O will be formed from the combustion of 8.064 g C6H12O6. Divide 8.064 g of glucose by its molar mass to get moles glucose. Multiply times the mol ratio 6mol H2O 1mol 8C6H12O6 from the balanced equation to get moles water.

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What is the ratio of hydrogen to oxygen in H2O?

Explanation: Equation: 2H 2 + O2 → H 2O. First, we need to calculate the moles of water. moles = mass molar mass. mass: 100g. molar mass: 1.008 ×2 +16 = 18.016. moles = 100 18.016 = 5.55062167. Now, we have to look at the ratio: hydrogen:oxygen:water = 2:1:1.

How many grams of H2O will be produced when glucose is burned?

The equation for the combustion of glucose is: C6H12O6 (s) + 6O2 (g) –>6CO2 (g) + 6H2O (g). How many grams of H2O will be produced when 8.064g of glucose is burned? 4.838 g H2O will be formed from the combustion of 8.064 g C6H12O6. Divide 8.064 g of glucose by its molar mass to get moles glucose.

What is the balanced equation for c6h5c2h5 + O2?

For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will. Compound states [like (s) (aq) or (g)] are not required. You can use parenthesis () or brackets [].

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